-6a^2-23a+20=0

Solution for -6a^2-23a+20=0 equation:

-6a^2-23a+20=0

a = -6; b = -23; c = +20;
Δ = b2-4ac
Δ = -232-4·(-6)·20
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1009}}{2*-6}=\frac{23-\sqrt{1009}}{-12}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1009}}{2*-6}=\frac{23+\sqrt{1009}}{-12}
$